Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.5 Exercises - Page 549: 39

Answer

$${\text{Divide }}{x^3}{\text{ by }}x - 5$$

Work Step by Step

$$\eqalign{ & \int {\frac{{{x^3}}}{{x - 5}}} dx \cr & {\text{The integrand is }}\frac{{{x^3}}}{{x - 5}},{\text{ the degree of the numerator is greater }} \cr & {\text{than the degree of the denominator, the integrand is not a proper}} \cr & {\text{function, so the first step is the long division: }} \cr & {\text{Divide }}{x^3}{\text{ by }}x - 5 \cr} $$
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