## Calculus 10th Edition

$\frac{2x-3}{x^3+10x}= \frac{A}{x} + \frac{Bx+C}{x^2+10}$
Rewrite using partial fraction decomposition First rewrite the denominator to simplify it to simplest terms $\frac{2x-3}{x(x^2+10)}$ Since there is a quadratic term, it must be written in the for Bx+C $\frac{2x-3}{x(x^2+10)} = \frac{A}{x} + \frac{Bx+C}{x^2+10}$