Answer
$\frac{2x-3}{x^3+10x}= \frac{A}{x} + \frac{Bx+C}{x^2+10} $
Work Step by Step
Rewrite using partial fraction decomposition
First rewrite the denominator to simplify it to simplest terms
$\frac{2x-3}{x(x^2+10)}$
Since there is a quadratic term, it must be written in the for Bx+C
$\frac{2x-3}{x(x^2+10)} = \frac{A}{x} + \frac{Bx+C}{x^2+10} $
