## Calculus 10th Edition

Published by Brooks Cole

# Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.5 Exercises: 3

#### Answer

$\frac{2x-3}{x^3+10x}= \frac{A}{x} + \frac{Bx+C}{x^2+10}$

#### Work Step by Step

Rewrite using partial fraction decomposition First rewrite the denominator to simplify it to simplest terms $\frac{2x-3}{x(x^2+10)}$ Since there is a quadratic term, it must be written in the for Bx+C $\frac{2x-3}{x(x^2+10)} = \frac{A}{x} + \frac{Bx+C}{x^2+10}$

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