Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.1 Exercises - Page 404: 49

Answer

$y= \frac{2}{5} (x-6)^{\frac{5}{2}} + 4(x-6)^{\frac{3}{2} } +C$

Work Step by Step

Find a general solution of the differential equation. $\frac{dy}{dx} = x\sqrt {x-6} $ $ \int dy = \int x\sqrt {x-6} dx$ Let $u=x-6$ and $x=u+6$ and $du=dx$ Substitute these values into the integrand $y = \int (u+6)u^{\frac{1}{2}}du$ $y= \int (u^{\frac{3}{2}} + 6u^{\frac{1}{2}}) du$ $y= \frac{2}{5} u^{\frac{5}{2}} + 4u^{\frac{3}{2}} +C$ $y= \frac{2}{5} (x-6)^{\frac{5}{2}} + 4(x-6)^{\frac{3}{2}} +C$, Resubstitute for u
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