Answer
$y=\frac{1}{2}sinx^{2}+c$
Work Step by Step
$\frac{dy}{dx}=xcosx^{2}$
$\int dy=\int xcosx^{2}dx$
let $u=x^{2}$
$du=2xdx$
$\int dy$ = $\frac{1}{2}\int cosudu$
$y=\frac{1}{2}sinx^{2}+c$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - 6.1 Exercises - Page 404: 46
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