Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 6 - Differential Equations - 6.1 Exercises - Page 404: 47

Answer

$-\frac{1}{2}cos(2x) +C$

Work Step by Step

First use separation of variables on the differential equation. $\frac{dy}{dx}= sin(2x)$ $\int dy= \int sin(2x) dx$, Use U substitution, making u=2x. $y= -\frac{1}{2}cos(2x) +C$
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