Answer
$4y^2= x^3$ passes through the point (4,4)
Work Step by Step
Use the general solution of the differential equation and plug in (4,4).
$y^2= Cx^3$
$16= 64C$
$C=\frac{1}{4}$
Substitute C back into the general solution
$ y^2= \frac{1}{4}x^3$
$4y^2= x^3$
