Answer
$x^{2}+y^{2}=Cy$
Work Step by Step
$2x=2yy'=Cy'$
$y'=(-2x)/(2y-C)$
$y'=(-2xy)/(2y^{2}-Cy)$
$y'=(-2xy)/(2y^{2}-(x^{2}+y^{2}) $
$y'=(-2xy)/(y^{2}-x^{2}) $
$y'=(2xy)/(x^{2}-y^{2})$
$x^{2}+y^{2}=Cy$
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