Answer
Yes
Work Step by Step
y=C_{1}e^{2x}+C_{2}e^{-2x}+C_{3}sin2x+C_{4}cos2x
y^{(4)}=16C_{1}e^{2x}+16C_{2}e^{-2x}+16C_{3}sin2x+16C_{4}cos2x
y^{(4)}-16y=0
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - 6.1 Exercises - Page 403: 19
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