Answer
No
Work Step by Step
$y=lnx, y'=\frac{1}{x} xy'-2y$
$\frac{1}{x} xy'-2$=$x(\frac{1}{x})-2lnx$
$x(\frac{1}{x})-2lnx$$\ne$$x^{3}e^{x}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - 6.1 Exercises - Page 403: 27
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