Answer
No
Work Step by Step
$y=sinx, y'=cosx $
$xy'-2y=x(cosx)-2(sinx)$
$x(cosx)-2(sinx)$ $\ne$$x^{3}e^{x}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 6 - Differential Equations - 6.1 Exercises - Page 403: 25
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