Answer
$\int\frac{12}{1+9x^{2}}=4\arctan(3x)+c$
Work Step by Step
$\int\frac{12}{1+9x^{2}}$
$=12\times\int\frac{1}{1+9x^{2}}$
$=12\times\int\frac{1}{1+(3x)^{2}}$
$=12\times\frac{1}{3} \arctan \frac{1}{\frac{1}{3}}x$
$=4\arctan(3x)+c$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.7 Exercises - Page 380: 4
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