Answer
$\text{False}$
Work Step by Step
This seems to be an application of the Fundamental Theorem of Calculus,
but there is a flaw...
The theorem requests that the integrand function be CONTINUOUS on the interval [a,b].
Here, the function $f(x)=\displaystyle \frac{1}{x}$ , at x=0$\in[-1,2]$
has a discontinuity, which is not removable.
The theorem does not apply.
The statement is false.