Answer
$\text{True}$
Work Step by Step
The RHS can be expanded with the logarithm product rule,
$\ln(M\cdot N)=\ln M+\ln N$
$RHS=\ln(|x|\cdot|c|)=\ln|x|+\ln|c|$
and, since for $c\neq 0, \ln|c|$ is a constant, C ,
the RHS is what we expected to see by the Log Rule,
$\displaystyle \int\frac{1}{x}dx=\ln|x|+C.$
The statement is true.
