Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises - Page 136: 8



Work Step by Step

$u=2-x^3$; $\dfrac{du}{dx}=-3x^2$ $y=5u^4; \dfrac{dy}{du}=20u^3$ $\dfrac{dy}{dx}=\dfrac{dy}{du}\times\dfrac{du}{dx}=20(2-x^3)^3(-3x^2)=-60x^2(2-x^3)^3.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.