Answer
$y'=-60x^2(2-x^3)^3.$
Work Step by Step
$u=2-x^3$; $\dfrac{du}{dx}=-3x^2$
$y=5u^4; \dfrac{dy}{du}=20u^3$
$\dfrac{dy}{dx}=\dfrac{dy}{du}\times\dfrac{du}{dx}=20(2-x^3)^3(-3x^2)=-60x^2(2-x^3)^3.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.4 Exercises - Page 136: 8
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
