Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises - Page 136: 55



Work Step by Step

$u=\tan{5\theta}$; $\dfrac{du}{d\theta}=5\times\sec^2{5\theta}=5\sec^2{5\theta}.$ $\dfrac{d}{du}f(u)=2u$ $\dfrac{d}{d\theta}f(\theta)=\dfrac{d}{du}f(u)\times\dfrac{du}{d\theta}=2\tan{5\theta}\times5\sec^2{5\theta}=10\tan{5\theta}\sec^2{5\theta}.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.