Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises - Page 136: 49



Work Step by Step

You can use the product rule to differentiate but it would be much easier to use the identity $(2\sin{x}\cos{x}=\sin{2x})$ to rewrite $h(x)$ as $\dfrac{\sin{4x}}{2}$ $u=4x$; $\dfrac{du}{dx}=4$ $\dfrac{d}{du}h(u)=\dfrac{\cos{u}}{2}$ $\dfrac{d}{dx}h(x)=\dfrac{d}{du}h(u)\times\dfrac{du}{dx}=2\cos{4x}.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.