Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises: 56



Work Step by Step

$u=\cos{8\theta}$; $\dfrac{du}{d\theta}=-8\sin{8\theta}$ $\dfrac{d}{du}g(u)=2u$ $\dfrac{d}{d\theta}g(\theta)=\dfrac{d}{du}g(u)\times\dfrac{du}{d\theta}=(2cos{8\theta})(-8\sin{8\theta})$ $=-16\cos{8\theta}\sin{8\theta}$ $=-8\sin{16\theta}.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.