Answer
$y'=12(4x-1)^2$
Work Step by Step
Using the Chain Rule:
$u=(4x-1) ; u'=4$
$f(u)=u^3 $; $ f'(u)=3u^2$
$f'(x)=(f'(u))(u')=4(3u^2)=12(4x-1)^2$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.4 Exercises - Page 136: 7
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