Answer
$\int_C (2x-y)dx+(x+3y)dy = 6$
Work Step by Step
The path is along y axis from $y=0$ to $y=2$
Hence, $x=0$ and $dx = 0$ on every point
$\therefore \int_C (2x-y)dx+(x+3y)dy \\
= \int_{y=0}^23ydy = [\frac{3y^2}{2}]_0^2 = 6$
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