Answer
$\int_C (xy dx + y dy) = \frac{190}{3}$
Work Step by Step
$x = 2t, y = 10t, dx = 2dt, dy = 10dt$
$\therefore \int_C (xy dx + y dy) \\
= \int_{t=0}^1(40t^2 +100t)dt\\
= [\frac{40t^3}{3}+50t^2]_0^1 = \frac{190}{3}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 15 - Vector Analysis - 15.2 Exercises - Page 1063: 53
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