Answer
$\int (x+3y^2)dx = 202$
Work Step by Step
$x = 2t, y = 10t , dx = 2dt$
$\int (x+3y^2)dx\\
= \int_0^1 (2t+300t^2).2dt\\
=[2t^2+200t^3]_0^1 = 202$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 15 - Vector Analysis - 15.2 Exercises - Page 1063: 52
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