Answer
$\int_C (2x-y)dx + (x+3y)dy = 25$
Work Step by Step
The path is along x axis from $x=0$ to $x=5$
Hence, $y=0$ and $dy = 0$ on every point
$\therefore \int_C (2x-y)dx+(x+3y)dy \\
= \int_{x=0}^52xdx = [\frac{2x^2}{2}]_0^5 = 25$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 15 - Vector Analysis - 15.2 Exercises - Page 1063: 55
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