Answer
$|f|=\sqrt 2$
Work Step by Step
$F(x, y)=i+j$
$|f|=\sqrt (1)^2$+$\sqrt (1)^2$ =$\sqrt 2$
$|f|=\sqrt 2$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 15 - Vector Analysis - 15.1 Exercises - Page 1049: 5
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