Answer
The Function Is Not Conservative because it does not satisfies conservative test
Work Step by Step
$f(x,y)=F$ (if conservative so let's check if it's conservative or not).
$M=\frac{1}{y}$ and $N=\frac{2x}{y^2}$.
taking partial derivative of M w.r.t Y and partial derivative of N w.r.t X so
Partial derivative of M w.r.t Y= $\frac{-1}{2y^{2}}$ and Partial derivative of N w.r.t X= $\frac{2}{y^{2}}$
As both are not equal so Vector Field is Not Conservative
