Answer
$$\frac{\partial f(x,y)}{\partial x}=2$$
$$\frac{\partial f(x,y)}{\partial y}=-5$$
Work Step by Step
The partial derivative with respect to $x$ is:
$$\frac{\partial f(x,y)}{\partial x}=\frac{\partial }{\partial x}(2x-5y+3)=2$$
because $y$ is treated as a constant.
The partial derivative with respect to $y$ is:
$$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y}(2x-5y+3)=-5$$
because now $x$is treated as a constant.