Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 13 - Functions of Several Variables - 13.3 Exercises - Page 896: 36

Answer

$$\frac{\partial z}{\partial x}=y^2\sinh xy^2$$ $$\frac{\partial z}{\partial y}=2xy\sinh xy^2$$

Work Step by Step

We will use chain rule to find both partial derivatives. The partial derivative with respect to $x$ is: $$\frac{\partial z}{\partial x}=\frac{\partial }{\partial x}(\cosh xy^2)=\sinh xy^2\frac{\partial }{\partial x}(xy^2)=\sinh xy^2\cdot y^2=y^2\sinh xy^2$$ because $y$ is treated as a constant. The partial derivative with respect to $y$ is: $$\frac{\partial z}{\partial y}=\frac{\partial }{\partial y}(\cosh xy^2)=\sinh xy^2\frac{\partial }{\partial y}(xy^2)=\sinh xy^2\cdot2xy=2xy\sinh xy^2$$ because now $x$ is treated as a constant.
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