Answer
\begin{array}{l}{\mathbf{r}(t)}{\text { is continuous on }[1, \infty)}\end{array}
Work Step by Step
Given$$\mathbf{r}(t)=\sqrt{t} \ \mathbf{i}+\sqrt{t-1} \ \mathbf{j}$$
Since we have $\sqrt{t} $, which is Continuous at $t\geq0$
and $ \sqrt{t-1} $ is continuous at $t\geq1$, we find:
\begin{array}{l}{\mathbf{r}(t)}{\text { is continuous on }[1, \infty)}\end{array}