Answer
$\lim\limits_{x\to1^-}\dfrac{x^2+2x+1}{x-1}=-\infty.$
Work Step by Step
$\lim\limits_{x\to1^-}\dfrac{x^2+2x+1}{x-1}=\dfrac{(1^-)^2+2(1^-)+1}{(1^-)-1}=\dfrac{4}{0^-}=-\infty.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - Review Exercises - Page 92: 73
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