Answer
$\lim\limits_{x\to0^+}\dfrac{\csc{2x}}{x}=+\infty.$
Work Step by Step
$\lim\limits_{x\to0^+}\dfrac{\csc{2x}}{x}=\lim\limits_{x\to0^+}\dfrac{1}{x\sin{2x}}=\dfrac{1}{(0^+)(\sin{[2(0^+)])}}=+\infty.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - Review Exercises - Page 92: 81
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