Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - Review Exercises - Page 92: 51

Answer

$f(x)$ has an irremovable (vertical asymptote) discontinuity at $x=5.$

Work Step by Step

The only restriction on $f(x)$'s domain is that $x\ne5.$ When $x=5,$ the denominator is $0;$ hence, the function has a vertical asymptote at $x=5.$ This discontinuity is not removable.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.