Answer
$\lim\limits_{x \to 2}\sin\dfrac{\pi x}{2}=0$
Work Step by Step
$\lim\limits_{x \to 2}\sin\dfrac{\pi x}{2}$
Apply direct substitution to evaluate the limit:
$\lim\limits_{x \to 2}\sin\dfrac{\pi x}{2}=\sin\dfrac{\pi(2)}{2}=\sin\pi=0$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 67: 30
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