Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 67: 27

Answer

$\lim\limits_{x \to \pi/2}\sin x=1$

Work Step by Step

$\lim\limits_{x \to \pi/2}\sin x$ Apply direct substitution to evaluate the limit: $\lim\limits_{x \to \pi/2}\sin x=\sin\dfrac{\pi}{2}=1$
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