## Calculus 10th Edition

a) $4.$ b) $16.$ c) $16.$
a)By Theorem $1.3:$ $\lim\limits_{x\to c} p(x)=p(c)$ $\lim\limits_{x\to-3}f(x)=-3+7=4.$ b)By Theorem $1.3:$ $\lim\limits_{x\to c} p(x)=p(c)$ $\lim\limits_{x\to4}g(x)=(4)^2=16.$ c)By Theorem $1.5: \lim\limits_{x\to c}(f(g(x)))=f(\lim\limits_{x\to c}g(x)).$ $\lim\limits_{x\to-3}g(f(x))=g(\lim\limits_{x\to-3}f(x))=g(4)=16.$