## Calculus 10th Edition

$(a)$ $\lim_{x\to4}g(x)=\dfrac{12}{5}$ $(b)$ $\lim_{x\to9}g(x)=2$
$g(x)=\dfrac{12(\sqrt{x}-3)}{x-9}$ The graph of the function is shown below: $(a)$ $\lim_{x\to4}g(x)$ From the graph, it can be seen that when $x$ approaches $4$ from the left and from the right, $g(x)$ approaches $\dfrac{12}{5}$ $\lim_{x\to4}g(x)=\dfrac{12}{5}$ $(b)$ $\lim_{x\to9}g(x)$ From the graph, it can be seen that when $x$ approaches $9$ from the left and from the right, $g(x)$ approaches $2$ $\lim_{x\to9}g(x)=2$