Answer
$e^{-x} = \sum\limits_{n=0}^{\infty} (-1)^n \frac{x^n} {n!}$ $\hspace{1cm}$ -We use $(-1)^n$ for alternate (-) signs
$\sum\limits_{n=0}^{\infty} (-1)^n \frac{x^n} {n!}$
Work Step by Step
-We use $(-1)^n$ for alternate (-) signs.
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 9 - Infinite Series - 9.8 Maclaurin And Taylor Series; Power Series - Exercises Set 9.8 - Page 667: 1
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