Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 13 - Partial Derivatives - 13.3 Partial Derivatives - Exercises Set 13.3 - Page 938: 55

Answer

4

Work Step by Step

z= x^{2}+3y^2 y=1 Thus x^{2}+3(1)^2 [putting the value of y] z=x^2+3 Differentiating, d(z)/dx=2x Thus at (2,1,7) dz/dx= (2*2)=4
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