Answer
4
Work Step by Step
$x^{4}$ - 1 = (x - 1)(x³ + x² + x + 1), so:
$\frac{x^{4}-1}{x-1}$ = x³ + x² + x + 1. Now we have:
$\lim\limits_{x \to 1^{+}}\frac{x^{4}-1}{x-1}$ = $\lim\limits_{x \to 1^{+}}x³ + x² + x + 1$ = 1³ + 1² + 1 + 1 = 4
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2 - Page 69: 7
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