## Calculus, 10th Edition (Anton)

Published by Wiley

# Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2 - Page 69: 10

#### Answer

$\lim\limits_{x \to 2}\frac{x² - 4x + 4}{x² + x - 6}$ = 0

#### Work Step by Step

x² - 4x + 4 = (x - 2)² x² + x - 6 = (x - 2)(x + 3) $\lim\limits_{x \to 2}\frac{x² - 4x + 4}{x² + x - 6}$ = $\lim\limits_{x \to 2}\frac{x-2}{x+3}$ = $\frac{2-2}{2+3}$ = 0

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