## Calculus, 10th Edition (Anton)

$\lim\limits_{x \to -1}\frac{2x²+x-1}{x+1}$ = -3
2x² + x - 1 = (x + 1)(2x - 1), so: $\frac{2x² + x - 1}{x+1}$ = 2x - 1 $\lim\limits_{x \to -1}\frac{2x²+x-1}{x+1}$ = $\lim\limits_{x \to -1}2x - 1$ = 2$\times$(-1) - 1 = -3