Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2 - Page 69: 21

Answer

$\lim\limits_{x \to 6^{+}}\frac{y+6}{y²-36}$ = +$\infty$

Work Step by Step

y² - 36 = (y + 6)(y - 6), so: $\frac{y+6}{y²-36}$ = $\frac{1}{y-6}$ $\lim\limits_{x \to 6^{+}}\frac{y+6}{y²-36}$ = $\lim\limits_{x \to 6^{+}}\frac{1}{y-6}$ = $\frac{1}{0^{+}}$ = +$\infty$
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