Calculus, 10th Edition (Anton)

Published by Wiley

Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2 - Page 69: 22

Answer

$\lim\limits_{y \to 6^{-}}\frac{y+6}{y²-36}$ = $-\infty$

Work Step by Step

y² - 36 = (y + 6)(y - 6) $\frac{y+6}{y²-36}$ = $\frac{1}{y-6}$ $\lim\limits_{y \to 6^{+}}\frac{y+6}{y²-36}$ = $\lim\limits_{y \to 6^{-}}\frac{1}{y-6}$ = $\frac{1}{0^{-}}$ = $-\infty$

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