## Calculus, 10th Edition (Anton)

Published by Wiley

# Chapter 1 - Limits and Continuity - 1.2 Computing Limits - Exercises Set 1.2: 26

#### Answer

$\lim\limits_{x \to 4}\frac{3-x}{x²-2x-8}$ does not exist.

#### Work Step by Step

As $\lim\limits_{x \to 4^{-}}\frac{3-x}{x²-2x-8}$ = +$\infty$ $\ne$ $\lim\limits_{x \to 4^{+}}\frac{3-x}{x²-2x-8}$ = -$\infty$, we conclude that $\lim\limits_{x \to 4}\frac{3-x}{x²-2x-8}$ does not exist.

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