Answer
$$\int_{1}^{4}\frac{e^{\sqrt{t}}}{\sqrt{t}}dt=2e^{2}-2e$$
Work Step by Step
$$let\ u =\sqrt{t},\,du=\frac{1}{2\sqrt{t}}dt$$
$$\int_{1}^{4}\frac{e^{\sqrt{t}}}{\sqrt{t}}dt=\int_{1}^{2}2e^{u}du$$
$$=\left [ 2e^{u} \right ]_{1}^{2}=2e^{2}-2e$$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 7 - Section 7.5 - Strategy for Integration - 7.5 Exercises - Page 522: 26
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
