Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 16 - Cumulative Review - Page 568: 24

Answer

The median of the numbers is $\text{median}=15.5$.

Work Step by Step

$\begin{align} & 15,12,10,9,15,22,7,23,12,8,18,22,11,30,14,18, \\ & 12,20,22,35,10,8,11,19,7,23,17,15,20,16,17,18, \\ & 22,15,20,13 \\ \end{align}$ Arrange the numbers in the ascending order, $\begin{align} & 7,7,8,8,9,10,10,11,11,12,12,12,13,14,15, \\ & 15,15,15,16,17,17,18,18,18,19,20,20,20 \\ & 22,22,22,22,23,23,30,35 \\ \end{align}$ The two middle numbers are $a=15$ and $b=16$ Since the number of terms are even, the median is the average of the two middle numbers as, $\text{median}=\frac{a\text{+}b}{2}$ And, $\begin{align} & \text{median}=\frac{\text{15+16}}{2} \\ & =\frac{\text{31}}{2} \\ & =15.5 \end{align}$ Hence, the median of the numbers is $\text{median}=15.5$.
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