Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 16 - Cumulative Review - Page 568: 6


The solution of the equation $2\left( 5y-3 \right)+4\left( 6y-1 \right)=17\left( 2y-3 \right)-25y$ is $y=-\frac{41}{25}$.

Work Step by Step

Solve the brackets first, $\begin{align} & 2\left( 5y-3 \right)+4\left( 6y-1 \right)=17\left( 2y-3 \right)-25y \\ & 10y-6+24y-4=34y-51-25y \end{align}$ Solve further, $\begin{align} & 10y-6+24y-4=34y-51-25y \\ & 10y+24y-34y+25y-6-4+51=0 \\ & 25y+41=0 \\ & 25y=-41 \end{align}$ Simplify, $y=-\frac{41}{25}$
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