Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 16 - Cumulative Review - Page 568: 11


The solution of the equation is $x=-\frac{1}{3},x=2$.

Work Step by Step

$\begin{align} & 3{{x}^{2}}-5x=2 \\ & 3{{x}^{2}}-5x-2=0 \end{align}$ Factorize the equation, $\begin{align} & 3{{x}^{2}}-5x-2=0 \\ & 3{{x}^{2}}-6x+x-2=0 \\ & 3x\left( x-2 \right)+1\left( x-2 \right)=0 \\ & \left( 3x+1 \right)\left( x-2 \right)=0 \end{align}$ Set each factor equal to zero and solve: $\begin{align} & \left( 3x+1 \right)\left( x-2 \right)=0 \\ & \left( 3x+1 \right)=0\text{ or }\left( x-2 \right)=0 \\ & 3x=-1\text{ or }x=2 \end{align}$ Then, $x=-\frac{1}{3},2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.