## Elementary Technical Mathematics

The area of the trapezoid is $A\approx 306\text{c}{{\text{m}}^{\text{2}}}$.
The area of the trapezoid is $A=\left( \frac{a+b}{2} \right)h$, Where, $a=16.8\text{cm}$, $b=22.4\text{cm}$ and $h=15.6\text{cm}$ Therefore, the area of the trapezoid is \begin{align} & A=\left( \frac{a+b}{2} \right)h \\ & =\left( \frac{16.8+22.4}{2} \right)15.6 \\ & =\left( \frac{39.2}{2} \right)15.6 \\ & =305.76 \end{align} Hence the area of the trapezoid is $A\approx 306\text{c}{{\text{m}}^{\text{2}}}$.