## Elementary Technical Mathematics

The side of the right-angle triangle is $a=19.9\text{m}$.
In a right-angle triangle, $\tan \left( a \right)=\frac{P}{B}$, Where $a=41.9{}^\circ$, $P=a$ and $B=22.2\text{m}$. Therefore, \begin{align} & \tan \left( 41.9{}^\circ \right)=\frac{a}{22.2} \\ & 0.89=\frac{a}{22.2} \\ & a=0.89\left( 22.2 \right) \\ & a=19.9\text{m} \end{align} Hence the side of the right-angle triangle is $a=19.9\text{m}$