Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 16 - Cumulative Review - Page 568: 16


The side of the right-angle triangle is $a=19.9\text{m}$.

Work Step by Step

In a right-angle triangle, $\tan \left( a \right)=\frac{P}{B}$, Where $a=41.9{}^\circ $, $P=a$ and $B=22.2\text{m}$. Therefore, $\begin{align} & \tan \left( 41.9{}^\circ \right)=\frac{a}{22.2} \\ & 0.89=\frac{a}{22.2} \\ & a=0.89\left( 22.2 \right) \\ & a=19.9\text{m} \end{align}$ Hence the side of the right-angle triangle is $a=19.9\text{m}$
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