## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 1 - Review - Page 101: 32

#### Answer

$\dfrac{3}{8}$

#### Work Step by Step

Convert the divisor to a mixed number to obtain: $=\dfrac{2}{3} \div \dfrac{9(1)+7}{9} \\=\dfrac{2}{3}\div \dfrac{16}{9}$ Use the rule $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}$ to obtain: $\require{cancel} =\dfrac{2}{3} \times \dfrac{9}{16} \\=\dfrac{2(9)}{3(16)} \\=\dfrac{\cancel{2}(\cancel{9}^3)}{\cancel{3}(\cancel{16}^8)} \\=\dfrac{1(3)}{1(8)} \\=\dfrac{3}{8}$

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