## Elementary Technical Mathematics

$14\dfrac{29}{48}$
Note that: $a\dfrac{b}{c} = a + \dfrac{b}{c}$ Thus, the given expression is equivalent to: $=5 + \dfrac{3}{16} + 9+ \dfrac{5}{12}$ Add the whole number parts to obtain: $=(5+9)+\dfrac{3}{16}+\dfrac{5}{12} \\=14+\dfrac{3}{16}+\dfrac{5}{12}$ Find the LCM of 12 and 16: $12 = 4(3) \\16 = 4(4)$ Thus, the LCM is $4(4)(3) = 48$. Make the fractions similar using their LCD which is $48$ to obtain: $=14 + \dfrac{3(3)}{16(3)} + \dfrac{5(4)}{12(4)} \\=14 + \dfrac{9}{48}+\dfrac{20}{48} \\=14 + \dfrac{9+20}{48} \\=14 + \dfrac{29}{48} \\=14\dfrac{29}{48}$